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- Instructor: Upali Siriwardane (Ph.D., Ohio State University)
- CTH 311, Tele: 257-4941, e-mail: upali@chem.latech.edu
- Office hours: 10:00 to 12:00 Tu & Th ; 8:00-9:00 and 11:00-12:00 M,W,& F
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- Tests will be given in regular class periods from 9:30-10:45
a.m. on the following days:
- September 22, 2004 (Test 1): Chapters 1 & 2
- October 6, 2004(Test 2): Chapters 3,
& 4
- October 20, 2004 (Test 3):
Chapter 5 & 6
- November 3, 2004 (Test 4):
Chapter 7 & 8
- November 15, 2004 (Test 5): Chapter
9 & 10
- November 17, 2004 MAKE-UP: Comprehensive
test (Covers all chapters
- Grading:
- [( Test 1 + Test 2 + Test3 +
Test4 + Test5)] x.70 + [ Homework + quiz average] x 0.30 = Final Average
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- We now put atoms and ions together to form compounds
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- 1. Classify compounds as ionic, covalent, or polar covalent bonds.
- 2. Write the formulas of compounds when provided with the name of the
compound.
- 3. Name common inorganic compounds using standard conventions and
recognize the common names of frequently used substances.
- 4. Predict the differences in physical state, melting and boiling
points, solid-state structure, and solution chemistry that result from
differences in bonding.
- 5. Draw Lewis structures for covalent compounds and polyatomic ions.
- 6. Describe the relationship between stability and bond energy.
- 7. Predict the geometry of molecules and ions using the octet rule and
Lewis structure.
- 8. Understand the role that molecular geometry plays in determining the
solubility and melting and boiling points of compounds.
- 9. Use the principles of VSEPR theory and molecular geometry to predict
relative melting points, boiling points, and solubilities of compounds.
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- Why have we been so interested in where the electrons are in an
atom? And what is the importance
of valence electrons?
- Valence e’s are involved in_______--the no of valence e’s has an
important influence on ______ of bonds formed. The filled inner core
does not directly affect bond formation.
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- Bonds are formed by a transfer of ________ from one atom to another or
by a ______ _________ between 2 atoms.
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- The elements’ symbol represents the inner core of electrons. Put a dot
for each valence electron around the symbol.
- Remember that the no. of valence electrons for the A groups is equal
to ?
- Each unpaired electron may be used in bond formation
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- So the ions formed by the
elements in:
- IA
- IIA
- IIIA
- VA
- VIA
- VIIIA
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- Extra stability has been noted for the noble gas configuration (8 e-s in
valence shell)--(for A elements)
- Ionic bonding
- Each atom in the ionic bond
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- Ionic compounds are formed between
- And
- When forming an ionic bond each atom in the bond attains a noble gas
configuration by a “complete” transfer of
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- An ionic bond is the electrostatic force that holds ions together in an
ionic compound
- An ionic bond is a very strong bond; ionic cmpds have high m and b pts.
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- Not all bonds are ionic.
- ________ bonds are bonds in which two (or more) electrons are ______ by
two atoms.
- One shared electron pair is
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- A reminder:
- Only valence electrons are involved in bonding. Group No. = # valence
e-s for A elements.
- Covalent bonds are formed
- Each atom in bond attains noble gas configuration by sharing of e-
pairs (H2 bond only
has 2 e-’s)
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- Look at formation of H2 molecule.
- H. +
.H
----> H:H (H-H)
- 1s1 1s1 bond formed by overlap of 1s
orbitals
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- Not all covalent bonds are formed btn the same 2 atoms (as H2,
homonuclear diatomic: _______sharing of e-’s in bond)
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- What about the bond in H-F?
- It is known that F is more likely to attract e-’s to itself than H,
leading to an unequal sharing of the e- pair.
- The covalent bond in which there is unequal sharing:
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- Electronegativity:
- .
- Eneg is a relative concept. Elements with
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- 0.2 - 0.5 will be a ________________ bond
- 0.5 - 1.6 will be a ________________ bond
- > 1.6 will be a ________________ bond
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- In general the _______ the difference in eneg btn the 2 atoms in the
bond, the ____ ______ the bond.
- If the difference is zero, bond (equal sharing of electron pair(s)
(H2, Cl2, O2, F2, N2)
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- If the difference is >0 and <1.9, have a : HCl (3.0 -
2.1); HF (4.0-2.1); OH (3.5-2.1)
- If the difference is > 1.9, have NaCl (3.0-0.9); CaO (3.5-1.0)
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- Which bond is the most polar (most ionic), which the least polar (most
covalent)?
- Li-F Be-F B-F C-F N-F O-F F-F
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- Express composition of molecules (smallest unit of covalent cmpds) and
ionic compounds in chemical symbols
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- Compounds are neutral overall. Therefore
- NaCl is array of Na+ and Cl- ions
- Na2S is array of Na+ and S2- ions
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- Potassium and chlorine
- Magnesium and bromine
- Magnesium and nitrogen
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- Just have to memorize
- NH4+
ammonium ion
- CO32-
carbonate ion
- CN- cyanide ion
- HCO3- hydrogen (or bi) carbonate ion
- OH- hydroxide
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- These polyatomic ions also form ionic cmpds when they are reacted with a
metal or a nonmetal in the case of the ammonium ion (or with each other
as ammonium sulfate). These polyatomic species act as a
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- So the formula for the cmpd formed btn the ammonium ion and sulfur would
be:
- and between calcium and the phosphate ion:
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- Ionic cmpds do not exist in discrete pairs of ions. Instead, in the
solid state, they exist as a three dimensional array--crystal lattice
--of cations and anions--are neutral overall,
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- potassium oxide
- magnesium acetate
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- Name the cation and anion but drop the word ion from both. This includes
the polyatomic ions.
- Na2S
- Ca3N2
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- Cu+ copper(I);
Cu2+ copper(II)
- So Cu2O is and
- CuO is
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- Ammonium chloride
- potassium cyanide
- silver oxide
- Magnesium chloride
- Sodium sulfate
- Iron(II) chloride
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- Name the parts as for ionic cmpds (CO: carbon and oxide) but tell how
many of each kind of atom by use of Greek prefixies. (Table 4.4)
- The mono- (for 1) may be omitted for the first element
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- Prefix meaning
- Mono- 1
- Di- 2
- Tri- 3
- Tetra- 4
- Penta- 5
- Hexa- 6
- Hepta- 7
- Octa- 8
- Nona- 9
- Deca- 10
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- CO
- CO2
- P4S10
- Boron trichloride
- Water H2O
Ammonia NH3
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- Diboron trichloride
- Sulfur trioxide
- Potassium sulfide
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- Remember covalent cmpds--
- A _________ is the smallest unit of a covalent cmpd that retains the
characteristics of the cmpd. Molecule - two or more atoms in a definite
arrangement held together by chemical bonds. (H2O, Cl2) [Cl2 is
considered a molecule but not a cmpd]
- Molecular cmpds exist as
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- Physical state:
- Ionic cmpds are
- Molecular cmpds can be
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- Melting (___________) and boiling (_________) pts
- In general the melting and boiling temps are much _______for ionic cmpds
than for molecular (covalent) cmpds. The ionic bond is very strong and
requires a lot of (heat) energy
to break the bond. The bond btn molecular species is not as
strong.
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- Structure in solid state:
- Ionic solids--
- Covalent solids--
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- In aqueous (H2O) solution:
- Ionic cmpds dissociate into the
- Many covalent cmpds when dissolved in water retain their structure and
molecular identity
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- Learn the names, formulas, charges, etc for those ions highlighted in
table 4.3.
- HCO3-: you should learn as bicarbonate
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- These rules are for covalently bonded cmpds only (btn 2 or more
nonmetals)
- Do not use them for ionic cmpds.
- 1. Count the total no. of valence electrons (the group no. is equal to
the no. of valence electrons).
- if the species is an anion, increase the no. of valence electrons by the
charge on the ion
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- if the species is a cation, subtract the charge of the cation from the
total no. of valence electrons.
- 2.Count the total no. of atoms, excluding H, in the molecule or ion.
Multiply that no. by 8.
- Exception: multiply the no. of H’s by 2.
- This tells you how many electrons you would need if you were putting 8
electrons around all atoms without any sharing of electrons (and 2
around all H’s).
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- 3. Subtract the no. of e-’s calculated in step 1 from the no. in step 2.
This gives you the no. of e-’s that must be shared to get an octet
around all atoms in the molecule.
- 4. no. of e-’s that must be shared /2 gives you the no. of bonds.
- 5. subtract the no. of e-’s that are shared (from step 3) from the total
no. of valence e-’s. This gives
you the no. of unshared e-’s.
- If you divide the no. of unshared e-’s by 2 you get the no. of lone
pairs.
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- Write the skeletal structure and fill in with the info you came up with.
After you’ve put in the # bonds calculated, fill in the octets.
- H (and F) form only one bond. Therefore they can only be terminal atoms
in a structure.
- So you can not have
- C---H---C
- It has to be H---C--C
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- Examples
- CH4
- PCl3
- SO32-
- NO3-
- CN-
- COBr2 (C is bonded to O and Br atoms)
- SO2
- H3O+ (hydronium
ion
- N3-
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- In general a triple bond (N2) is ________ than a double bond
(O2) which is ________than a single bond (F2).
- Bond order: BO of 1--single bond, BO of 2-- -double bond, BO of 3
--triple bond.
- The stronger the bond,
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- Resonance structure –1 of 2 or more Lewis structures for a molecule
(ion) that can’t be represented with a single structure
- Resonance – use of
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- Each resonance structure contributes to the actual structure
- no single structure is a complete description
- positions of atoms must be the same in each, only electrons are moved
around
- actual structure is an “average”
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- Draw resonance structures for SO3 and N3-.
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- There are three classes of exceptions to the octet rule.
- 1) Molecules with an odd number of electrons;
- 2) Molecules in which one atom has less than an octet;
- 3) Molecules in which one atom has more than an octet.
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- Electrostatic forces in ionic bonds is _____________. But species with
covalent bonds have electron pairs concentrated btn 2 atoms and is ..
- We use VESPR theory to predict the shape of the covalently bound
species.
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- Most stable geometry is one in which electron pairs (electron clouds)
are as
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- The geometry is determined by the atoms present in the species. See
atoms that are bonded to other atoms. Don’t “see” lone pairs but they
influence geometry
- I. Diatomics (2 atoms only):
always ________
- H2, HCl, CO X----X
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- II. Polyatomic (3 or more atoms) species: Use VSEPR model to
predict shapes
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- 1. Do Lewis structure
- 2. Count total e- pairs (clouds) around central atom (A). Multiple bonds
count as one electron pair (cloud). In reality multiple bonds are bigger
than single bonds (electron clouds larger).
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- 3. Separate e- pairs into bonded pairs (B) and lone pairs (E)
- 4. Apply table that I give you.
- 5. Remember that lone pairs of e-’s are invisible, but their presence
affects the final molecular geometry!!!!!
- Lone e- pair-lone e-pairs are more repulsive than bonded pair-lone pair
repulsions or bonded pair-bonded pair repulsions.
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- 2 electron clouds around a central atom (A)
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- # e # bonded #lone pairs geom angle clouds pairs pairs
- 2
- 3
- 3
- 4
- 4
- 4
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- H2S
- SO2
- CO2
- CF4
- H2CO
- ClO3-
- ClO2-
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- A molecule is polar if its centers of positive and negative charges do
not coincide. If a molecule is polar we say that it acts as a dipole. In
an electric field nonpolar molecules (positive and negative centers
coincide) do not align with the
field but polar molecules do.
- Next we will see why this happens and the implications.
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- I. Diatomics, A-B
- a.If A = B have homonuclear diatomic;
has
- b. A ≠ B have heteronuclear diatomic
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- II. Polyatomic species are more complicated.
- Let’s look at VSEPR cases considered.
- General rule (my rule):
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- H2S
- SO2
- CO2
- CF4
- AlCl3
- CHCl3
- SCl2
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- Intramolecular forces: within a molecule--bonds
- Intermolecular forces: between molecules--these determine important
properties as melting and boiling points and solubility
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- Like dissolves like:
- Polar cmpds dissolve in polar
solvents as ionic and polar cmpds (HCl) in water
- Nonpolar cmpds dissolve in nonpolar solvents: oils in CCl4
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- Stronger the intermolecular forces the higher the melting and boiling
points
- In general for cmpds of similar weight: polar moleculaes have stonger
forces than nonpolar cmpds
- In general for similar structure the greater the mass the stronger the
forces
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- CO and NO
- F2 and Br2
- CH3CH2OH
and CH3CH3
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