Homework Problems: Chapter 5
            multiply by which of the following factors?
a. 6.02 x 1023 atoms/1 mol b. 1 mol/6.02 x 1023 atoms c. 1.66 x 10-24 atoms/1 mol
d. 1 mol/1.66 x 10-24 atoms
a. 1.41 x 1024 b. 3.41 x 1023 c. 2.41 x 1024 d. 6.45 x 1024
             weight: S, 32.06 g/mol]
a. 1.81 x 1024 g b. 32.06 g   c. 3.01 g    d.
0.150 g               e. 96.5 g
a. 0.0107 g b. 3.50 g c. 112 g d. 1.75 g e. 0.0046 g
a.  1.10 x 1023   b. 1.43 x 1023 c.
6.27 x 1022 d. 2.53 x 1026 e. 5.78 x 1026
         ___N2(g) + ___H2(g)
--> ___NH3(g)
The coefficient of the hydrogen in the balanced
equation is
             a.  1.  
b.  2.    c.  3.    d. 
6.
                  C2H6(g) + O2(g)
------> CO2(g) + 
H2O(g) 
 a.
13       b. 15    c.
17     d. 19       e. 21 
with
chlorine? H2(g) + Cl2(g) ------> HCl(g) (unbalanced)
a.
0.5 mol b. 1 mol c. 2 mol d. 4 mol e. 8 mol
11.  For the reaction given below, how many moles of AlBr3
will be produced if 12 moles of Br2 
react with 8 moles of aluminum?
          2Al(s)  +  3Br2(l)  ---> 
2AlBr3(s)
a.       4    b. 8    c. 12   d. 16 
e. 20
                  
  2Na(s) 
+  Cl2(g)  ---> 
2NaCl(g)
a. 4.3 g   b. 9.2 g 
c. 14.2 g  d. 18.8 g e. 33.0 g
a. limiting reactant b. theoretical yield c. percent yield d. molecular weight of the product e. stoichiometric coefficients
14.     If 95.0 g of cesium reacts in sufficient
chlorine to produce cesium chloride, what is the theoretical yield?
2Cs(s)  +  Cl2(g)    ---> 
2CsCl(s)  
a.     95.0 g  
   b. 120. g          c.
146 g            d.
236 g           e.
285 g
a. 50.5 %       b. 91.1 %       c. 85.7 %        d.  100 %