Homework Problems: Chapter 5
multiply by which of the following factors?
a. 6.02 x 1023 atoms/1 mol b. 1 mol/6.02 x 1023 atoms c. 1.66 x 10-24 atoms/1 mol
d. 1 mol/1.66 x 10-24 atoms
a. 1.41 x 1024 b. 3.41 x 1023 c. 2.41 x 1024 d. 6.45 x 1024
weight: S, 32.06 g/mol]
a. 1.81 x 1024 g b. 32.06 g c. 3.01 g d.
0.150 g e. 96.5 g
a. 0.0107 g b. 3.50 g c. 112 g d. 1.75 g e. 0.0046 g
a. 1.10 x 1023 b. 1.43 x 1023 c.
6.27 x 1022 d. 2.53 x 1026 e. 5.78 x 1026
___N2(g) + ___H2(g)
--> ___NH3(g)
The coefficient of the hydrogen in the balanced
equation is
a. 1.
b. 2. c. 3. d.
6.
C2H6(g) + O2(g)
------> CO2(g) +
H2O(g)
a.
13 b. 15 c.
17 d. 19 e. 21
with
chlorine? H2(g) + Cl2(g) ------> HCl(g) (unbalanced)
a.
0.5 mol b. 1 mol c. 2 mol d. 4 mol e. 8 mol
11. For the reaction given below, how many moles of AlBr3
will be produced if 12 moles of Br2
react with 8 moles of aluminum?
2Al(s) + 3Br2(l) --->
2AlBr3(s)
a. 4 b. 8 c. 12 d. 16
e. 20
2Na(s)
+ Cl2(g) --->
2NaCl(g)
a. 4.3 g b. 9.2 g
c. 14.2 g d. 18.8 g e. 33.0 g
a. limiting reactant b. theoretical yield c. percent yield d. molecular weight of the product e. stoichiometric coefficients
14. If 95.0 g of cesium reacts in sufficient
chlorine to produce cesium chloride, what is the theoretical yield?
2Cs(s) + Cl2(g) --->
2CsCl(s)
a. 95.0 g
b. 120. g c.
146 g d.
236 g e.
285 g
a. 50.5 % b. 91.1 % c. 85.7 % d. 100 %