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3H2(g) +
N2(g) ------> 2NH3(g)
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3 mol H2
(reactant) = 1 mol N2 (reactant) consumed
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3 mol H2
(reactant) = 2 mol NH3 (products)
produced
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1 mol N2
(reactant) = 2 mol NH3 (products) produced
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3 x 2 (6) g
H2 (reactant) = 1x 28 (28)mol
N2 (reactant) consumed
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3 x 2 H2
(6) (reactant) = 2x
17 (34) NH3 (products) produced
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1 x 28
(28) g N2 (reactant) = 2 x 17 (34)
NH3 (products) produced
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