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| • | Now figure out
how to get the same no of |
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| atoms of each
kind on both sides by using |
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| whole no
coefficients in front of the species. |
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| • | As H2 + _N2 NH3,
then |
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| • | H2 + _N2 _ NH3, then |
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| • | _ H2 + _N2 _ NH3 |
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| • | Now have _ H’s,
_N’s on both sides and the |
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| lowest set of
whole no coefficients have |
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| been used. The equation is balanced. |
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