CHEM 120: Introduction to
Inorganic Chemistry
 
  |  |  | 
 
  |  | Instructor: Upali Siriwardane (Ph.D.,
  Ohio State University) | 
 
  |  | CTH 311, Tele: 257-4941, e-mail:
  upali@chem.latech.edu | 
 
  |  | Office hours: 10:00 to 12:00 Tu &
  Th ;  8:00-9:00 and 11:00-12:00  M,W,& F | 
 
  |  |  | 
Chapters Covered and Test
dates
 
  |  |  | 
 
  |  | Tests will be given in regular class
  periods  from  9:30-10:45 a.m. on the following days: | 
 
  |  | September 22,    
  2004 (Test 1): Chapters 1 & 2 | 
 
  |  | October 8,           2004(Test 2):  Chapters  3,
  & 4 | 
 
  |  | October 20,        
  2004 (Test 3): Chapter  5 & 6 | 
 
  |  | November 3,       
  2004 (Test 4): Chapter  7 & 8 | 
 
  |  | November 15,     
  2004 (Test 5): Chapter  9 & 10 | 
 
  |  | November 17,     
  2004 MAKE-UP: Comprehensive test (Covers all chapters | 
 
  |  | Grading: | 
 
  |  | [(
  Test 1 + Test 2 + Test3 + Test4 + Test5)] x.70 + [ Homework + quiz average] x
  0.30 = Final Average | 
 
  |  | 5 | 
Chapter 5. Calculations
and the Chemical Equation
The mole concept and
atoms
 
  |  |  | 
 
  |  | In ch 1 we learned that					 1 amu =
  1.661 x 10-24 g | 
 
  |  |  | 
 
  |  | So if the average mass of a gold atom
  is196.97 amu x 1.661 x 10-24 g 
  = 3.27 x 10-22 g 		 
  	         1 amu | 
 
  |  | a very
  small no. | 
"Where did I get the..."
 
  |  |  | 
 
  |  | Where did I get the 196.97 anu for the
  mass of one Au atom? | 
 
  |  | From the ____________________!!! | 
 
  |  | If I write amu after these nos. it
  implies that I have the mass of ______ atom of that element (in amu). | 
 
  |  | But 3.27 x 10-22 g is too
  small an amt to work with in the lab. | 
 
  |  | What to do? | 
 
  |  | Scale up to quantities that we can
  handle by | 
Avogadro’s number
 
  |  |  | 
 
  |  | Defining  one mole (mol) as amt of substance that
  contains as many elementary entities 
  (atoms, molecules, ions , etc) as there are in atoms in exactly 12 g
  of the carbon-12 isotope. This is determined experimentally and is…... | 
 
  |  |  | 
Slide 7
Useful relationship
 
  |  |  | 
 
  |  | # moles X = #g X/molar mass X | 
Some problems
 
  |  |  | 
 
  |  | How many atoms are there in 5.10 moles
  of sulfur? What’s the mass of 5.10 moles of S? | 
 
  |  |  | 
 
  |  | How many moles of calcium atoms are in
  1.16 x 1024 atoms of Ca? How many grams? | 
"Which of the
following has..."
 
  |  |  | 
 
  |  | Which of the following has more atoms:
  1.10g of hydrogen atoms or 14.7 g of chromium atoms? | 
 
  |  |  | 
 
  |  | How many moles are in 0.040 kg Na? | 
 
  |  |  | 
"What’s the mass,"
 
  |  |  | 
 
  |  | What’s the mass, in grams, of one atom
  of potassium? | 
 
  |  | One atom of some element has a mass of
  1,45 x 10-22 g. Identify the element. | 
 
  |  |  | 
Compounds
 
  |  |  | 
 
  |  | The chemical formula: | 
 
  |  | MgO  (ion pair) | 
 
  |  | H2O | 
 
  |  | C12H22O11 | 
 
  |  | Ca3(PO4)2 | 
 
  |  | CuSO4.5H2O  vs 
  CuSO4 | 
The mole concept applied
to compounds
 
  |  |  |  | 
 
  |  | The formula weight of a species is the
  sum of atomic masses (amu) of the atoms in a species. | 
 
  |  | Formula weight of NH3 | 
 
  |  |  | 
 
  |  |  | 
 
  |  | For an ionic compound | 
 
  |  | MgF2 = | 
"In general we talk
about"
 
  |  |  | 
 
  |  | In general we talk about | 
 
  |  | moles for covalent compounds | 
 
  |  | formula units rather than moles of
  ionic compounds. | 
 
  |  |  | 
Molar mass
 
  |  |  | 
 
  |  | Mass of one mole of NH3: | 
 
  |  | Mass of 6.022 x 1023 molecules of
  NH3 is | 
 
  |  |  | 
 
  |  | Mass of one molecule of NH3
  is. | 
 
  |  |  | 
"Mass of one mole of..."
 
  |  |  | 
 
  |  | Mass of one mole of MgF2 is | 
 
  |  | Mass of one formula unit  of MgF2 is | 
 
  |  |  | 
 
  |  | Mass of 6.022 x 1023 formula
  units of MgF2 is | 
"Calc the molar"
 
  |  |  | 
 
  |  | Calc the molar  mass of Ca(NO3)2. | 
 
  |  |  | 
 
  |  |  | 
 
  |  | Calc the molar mass of a compound if
  0.372 mol of it has a mass of 152g. | 
 
  |  |  | 
"5.38."
 
  |  |  | 
 
  |  | 5.38. How many grams of each are
  required to have 0.100 mol of | 
 
  |  | A. NaOH | 
 
  |  |  | 
 
  |  | B. H2SO4 | 
 
  |  |  | 
 
  |  | C. C2H5OH | 
 
  |  |  | 
 
  |  | D. Ca3(PO4)2 | 
"5.40."
 
  |  |  | 
 
  |  | 5.40. How many moles are in 50.0 g of | 
 
  |  | A. CS2 | 
 
  |  |  | 
 
  |  | B. Al2(CO3)3 | 
 
  |  |  | 
 
  |  | C. Sr(OH)2 | 
 
  |  |  | 
 
  |  | D. LiNO3 | 
"Calc the no."
 
  |  |  | 
 
  |  | Calc the no. of C, H, and  O atoms in 1.50 g of glucose (C6H12O6). | 
 
  |  |  | 
 
  |  |  | 
 
  |  | What is the average mass of one C3H8
  molecule? | 
 
  |  |  | 
 
  |  |  | 
 
  |  | What is the mass of 5.00 x 1024
  molecules of NH3? | 
 
  |  |  | 
Law of conservation of
mass
 
  |  |  | 
 
  |  | Mass is neither created nor destroyed
  in an ordinary chemical rxn. | 
 
  |  | Or the sum of the masses  of the reactants is equal to the sum of the masses
  of the products | 
"mercury + oxygen
---> mercury(II)oxide"
 
  |  |  | 
 
  |  | mercury + oxygen --->
  mercury(II)oxide | 
 
  |  | 10.03g      
  ?                     10.83g | 
 
  |  |  | 
 
  |  |  | 
 
  |  | Easier to use symbols for chem eqns. | 
 
  |  |  | 
"reactants g"
 
  |  |  | 
 
  |  | reactants g  products | 
 
  |  | lhs            rhs | 
 
  |  | may indicate physical state by (s),
  (g), (l), (aq)-aqueous solution | 
 
  |  | Remember that H2,N2,O2,F2,Cl2,Br2,I2
  occur as diatomics in nature and are used as diatomics in chemical eqns | 
"To balance:"
 
  |  |  | 
 
  |  | To balance: Have to have same no of
  each kind of atom on both sides of the eqn. The bonding arrangement changes,
  but the no of each kind of atom doesn’t change. | 
 
  |  |  | 
Slide 25
Slide 26
Balancing chemical eqns
 
  |  |  | 
 
  |  | Use correct formulas for the reactants
  and products (if word eqn at start) | 
 
  |  | Balance by putting coefficients (nos)
  in front of the formulas. You may not change the formulas! These coefficients
  are called the stoichiometric (measure of mass) coefficients. | 
 
  |  | By convention use the lowest set of
  whole no. coefficients to balance. | 
"Start by balancing
elements that..."
 
  |  |  | 
 
  |  | Start by balancing elements that appear
  only once on each side of the equation | 
 
  |  | Balance remaining elements | 
 
  |  | Check your balanced equation! | 
 
  |  | To predict products--do an experiment | 
To balance
 
  |  |  | 
 
  |  | hydrogen + nitrogen  g ammonia | 
 
  |  | 1. write the symbols for the species in
  the rxn | 
 
  |  |  | 
 
  |  |  | 
"Now figure out how
to..."
 
  |  |  | 
 
  |  | Now figure out how to get the same no
  of atoms of each kind on both sides by using whole no coefficients in front
  of the species. | 
 
  |  | As      
  H2  + _N2 g
  NH3, then | 
 
  |  | H2  + _N2 g _ NH3,  then | 
 
  |  | _ H2  +  _N2
  g _ NH3 | 
 
  |  | Now have _ H’s, _N’s on both sides and
  the lowest set of whole no coefficients have been used.  The equation is balanced. | 
 
  |  |  | 
"3H2 + N2
g 2NH3"
 
  |  |  | 
 
  |  | 3H2 + N2 g 2NH3 | 
 
  |  | 3 mol of H2 reacts with 1
  mol of N2 to form 2 mol of NH3 | 
 
  |  | 3 molecules of H2 reacts
  with 1 molecule of N2 to form 2 molecules of NH3 | 
 
  |  | 6H + 2N reacts to give 6H and 2N | 
 
  |  | 6g of H2 reacts with 28 g of
  N2 to form 34g of NH3 | 
 
  |  | Note that | 
Balance
 
  |  |  | 
 
  |  | C2H6 + O2
  g CO2 + H2O | 
 
  |  |  | 
 
  |  | H2O2 g H2O
  + O2 | 
 
  |  |  | 
 
  |  | C2H5OH + O2
  g CO2 + H2O | 
 
  |  |  | 
 
  |  | KOH + H3PO4 g K3PO4  + H2O | 
 
  |  |  | 
 
  |  | N2O5 g N2O4
  + O2 | 
Balance
 
  |  |  | 
 
  |  | NH4NO3 g N2O  +  H2O | 
 
  |  |  | 
 
  |  | NH4NO2 g N2   + H2O | 
 
  |  |  | 
 
  |  | Be2C + H2O g
  Be(OH)2 + CH4 | 
 
  |  |  | 
 
  |  | NH3 + CuO g Cu + N2
  + H2O | 
 
  |  |  | 
Balance
 
  |  |  | 
 
  |  | S2Cl2(s) + NH3(g)  g  N4S4(s)
  + NH4Cl(s) + S8(s) | 
Calculations using the
chemical eqn
 
  |  |  |  | 
 
  |  | Quantitative study of reactants and
  products in a chemical reaction | 
 
  |  | How much product will be formed? | 
 
  |  | How much reactant is needed? | 
 
  |  | Use coefficients in a balanced equation
  to convert between moles of different substances in a chemical reaction. | 
Chemical Reaction
 
  |  |  | 
 
  |  | 3H2(g)  +   
  N2(g) ------>  2NH3(g) | 
 
  |  |  | 
 
  |  | 3 mol H2 (reactant) = 1 mol
  N2 (reactant)  consumed | 
 
  |  | 3 mol H2 (reactant) =  2 mol NH3 (products) produced | 
 
  |  | 1 mol N2 (reactant) = 2 mol
  NH3 (products) produced | 
 
  |  | 3 x 2 (6) g H2 (reactant) =
  1x 28  (28)mol N2
  (reactant)  consumed | 
 
  |  | 3 x 2 H2 (6) (reactant)
  =  2x 17 (34) NH3 (products)
  produced | 
 
  |  | 1 x 28 (28) g N2 (reactant)
  = 2 x 17 (34) NH3 (products) produced | 
Chemical reactions
 
  |  |  | 
 
  |  | Hydrogen reacts with nitrogen to form
  NH3. | 
 
  |  | theoretically  it is should be that when 6 g of hydrogen
  reacts completely with  28 g of
  nitrogen,  34 g of ammonia is formed. | 
 
  |  | However in real chemical reactions actual
  __ g of hydrogen reacting with __ g of nitrogen,  __ g of ammonia is produced need be
  experimentally determined. | 
 
  |  |  | 
2H2 + O2
g 2H2O
2H2 + O2
g 2H2O
 
  |  |  | 
 
  |  | How many moles of H2  is needed to completely react with19.8 mol
  O2? | 
 
  |  |  | 
 
  |  | How many moles of H2O are
  formed when 25.4 mol of H2 react? | 
 
  |  |  | 
2H2 + O2
g 2H2O
 
  |  |  | 
 
  |  | How many moles of H2 react
  with 38 g of O2? | 
 
  |  |  | 
 
  |  | What mass of H2O is formed
  when 59.0g of H2 reacts completely with O2?  How much O2 reacted in this
  case? | 
Mass relationships
in chemical equations
 
  |  |  |  | 
 
  |  | Mole-to-mole conversions | 
 
  |  | use mole ratios as conversion factors | 
 
  |  | Mass-to-mole and mole-to-mass
  conversions | 
 
  |  | use molecular weights as conversion
  factors | 
 
  |  | Mass-to-mass conversions | 
 
  |  | do in multiple steps | 
General prescription
Problems
 
  |  |  | 
 
  |  | How many grams of Al2O3
  can be produced from 15.0 g Al? | 
 
  |  | 4 Al(s) + 3O2(g) g 2Al2O3(s) | 
"C3H8
+"
 
  |  |  | 
 
  |  | C3H8 +  O2 g CO2 + H2O    balance | 
 
  |  | How many mol of O2 does it
  take to completely burn 7.0 mol of C3H8? | 
 
  |  | How many mol each of CO2 and
  H2O are produced? | 
 
  |  | How many grams of oxygen does it take
  to completely burn 25.0 g of C3H8? | 
 
  |  | How many grams each of CO2
  and H2O are produced when 25.0 g of C3H8 is
  burned? | 
"A 4.00 g sample of..."
 
  |  |  | 
 
  |  | A 4.00 g sample of Fe3O4
  reacts with O2 to produce Fe2O3. | 
 
  |  | 4Fe3O4(s) + O2(g)g   6Fe2O3(s) | 
 
  |  |  | 
 
  |  | Determine the no. of grams of Fe2O3
  produced. | 
Theoretical and percent
yield
 
  |  |  |  | 
 
  |  | How good an experimentalist are you? | 
 
  |  | What if 100% of reactants are not
  converted to desired products? | 
 
  |  | Frequently happens because of “side
  reactions” (other products), handling, etc. | 
 
  |  | 100% amount is theoretical yield | 
 
  |  | Amount obtained is actual yield | 
 
  |  |  | 
"Theoretical yield -
amount of..."
 
  |  |  | 
 
  |  | Theoretical yield - amount of product
  that would result if all limiting reagent gave only product | 
 
  |  | Actual yield - the amount of product
  actually obtained from a reaction (almost always less than the theoretical
  yield) | 
 
  |  | Percent yield - calculated by | 
 
  |  | % yield = actual yield     ´ 100% | 
 
  |  | theoretical yield | 
"Theoretical yield
is what we..."
 
  |  |  | 
 
  |  | Theoretical yield is what we calculate
  assuming 100% conversion of reactants to products. | 
 
  |  |  | 
 
  |  |  | 
 
  |  | In the combustion of 33.5g of C3H6,
  16.1 g of H2O is isolated. What is the percent yield? | 
"If the % yield of..."
 
  |  |  | 
 
  |  | If the % yield of Fe2O3
  in problem was 90.0% what was the actual yield of Fe2O3? | 
"A 3.5 g sample of..."
 
  |  |  | 
 
  |  | A 3.5 g sample of water reacts with PCl3
  according to :						3H2O + PCl3 g H3PO3
  + 3HCl. | 
 
  |  | How many grams of H3PO3
  are produced? | 
 
  |  |  |