Combustion Analysis Sample Problem #1

Benzene is a liquid compound composed of carbon and hydrogen. A sample of benzene weighing 342 mg is burned in excess oxygen and forms 1156 mg of carbon dioxide. What is the percent composition of benzene?

[92.25% C & 7.75% H]

If a compound contains oxygen as well as carbon and hydrogen, the mass of the oxygen can be determined by subtracting the masses of the carbon and the hydrogen from the total mass of the compound.

mass of O = mass of compound – [mass of C + mass of H]

Combustion Analysis Sample Problem #2

n-Butyl phthalate is used as an insect repellant and is composed of carbon, hydrogen, and oxygen. When a 0.3413 g sample was subjected to combustion analysis, 0.2430 g of water and 0.8633 g of carbon dioxide were produced. In another analysis, the molecular weight was determined to be 278.38 g/mol. Calculate the empirical formula and the molecular formula.

[empirical formula = C8H11O2 & molecular formula = C16H22O4]

Combustion Analysis Sample Problem #3

When a 1.0000 g sample of a vitamin C was combusted, 1.4991 g of CO2 and 0.4092 g of H2O were isolated. Calculate the percent composition and empirical formula of vitamin C.

[40.909% C, 4.587% H, 54.504% O & empirical formula = C3H4O3]

In another analysis the molecular mass of vitamin C was found to be 176.14. What is the molecular formula of vitamin C? [C6H8O6]

Combustion Analysis Sample Problem #4

A 1.500 g sample of hydrocarbon undergoes complete combustion to produce 4.400 g of CO2 and 2.700 g of H2O. What is the empirical formula of this compound? [CH3]

Combustion Analysis Sample Problem #5

A 0.250 g sample of hydrocarbon undergoes complete combustion to produce 0.845 g of CO2 and 0.173 g of H2O. What is the empirical formula of this compound? [CH]

Combustion Analysis Sample Problem #6

A 0.1034 g sample of a compound composed of carbon, hydrogen and oxygen is subjected to combustion analysis, producing 0.2351g CO2 and 0.0962 g H2O. What is the empirical formula for the compound? [C3H6O]

If the molecular weight is 116.18 g/mol, what is the molecular formula?

[C6H12O2]